Sides of triangle | Some Applications of Trigonometry | CBSE | Class 10 | Math

Sides of triangle | Some Applications of Trigonometry | CBSE | Class 10 | Math

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This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

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5 episodios
episode Q5. In the given figure, angle ACB = 90 and CD is perpendicular to AB. Prove that CD x CD = BD. AD artwork
Q5. In the given figure, angle ACB = 90 and CD is perpendicular to AB. Prove that CD x CD = BD. AD

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 4 min
episode Q4. The side AD of a parallelogram ABCD is produced to a point E. BE intersects CD at F. Show that triangle ABE is similar to triangle CFB. artwork
Q4. The side AD of a parallelogram ABCD is produced to a point E. BE intersects CD at F. Show that triangle ABE is similar to triangle CFB.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 2 min
episode Q3. In the given figure PA, QB and RC each is perpendicular to AC such that PA-x, RC y, QB=z, AB=a and BC=b. Prove that 1/x + 1/y = 1/z artwork
Q3. In the given figure PA, QB and RC each is perpendicular to AC such that PA-x, RC y, QB=z, AB=a and BC=b. Prove that 1/x + 1/y = 1/z

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 4 min
episode Q2. In triangle ABC, AD is perpendicular to BC and AD x AD = BD.CD .Prove that angle BAC = 90. artwork
Q2. In triangle ABC, AD is perpendicular to BC and AD x AD = BD.CD .Prove that angle BAC = 90.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 4 min
episode Q1. Diagonals AC and BD of a trapezium ABCD with AB II DC intersect each other at point 0. Using similarity criteria for two triangles, show that OA/OC = OB/OD. artwork
Q1. Diagonals AC and BD of a trapezium ABCD with AB II DC intersect each other at point 0. Using similarity criteria for two triangles, show that OA/OC = OB/OD.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 2 min
Muy buenos Podcasts , entretenido y con historias educativas y divertidas depende de lo que cada uno busque. Yo lo suelo usar en el trabajo ya que estoy muchas horas y necesito cancelar el ruido de al rededor , Auriculares y a disfrutar ..!!
Junior Cissé
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Muy buenos Podcasts , entretenido y con historias educativas y divertidas depende de lo que cada uno busque. Yo lo suelo usar en el trabajo ya que estoy muchas horas y necesito cancelar el ruido de al rededor , Auriculares y a disfrutar ..!!
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Fantástica aplicación. Yo solo uso los podcast. Por un precio módico los tienes variados y cada vez más.
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Me encanta la app, concentra los mejores podcast y bueno ya era ora de pagarles a todos estos creadores de contenido
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