Sides of triangle | Some Applications of Trigonometry | CBSE | Class 10 | Math

Sides of triangle | Some Applications of Trigonometry | CBSE | Class 10 | Math

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

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5 episodios
episode Q5. In the given figure, angle ACB = 90 and CD is perpendicular to AB. Prove that CD x CD = BD. AD artwork
Q5. In the given figure, angle ACB = 90 and CD is perpendicular to AB. Prove that CD x CD = BD. AD

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 4 min
episode Q4. The side AD of a parallelogram ABCD is produced to a point E. BE intersects CD at F. Show that triangle ABE is similar to triangle CFB. artwork
Q4. The side AD of a parallelogram ABCD is produced to a point E. BE intersects CD at F. Show that triangle ABE is similar to triangle CFB.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 2 min
episode Q3. In the given figure PA, QB and RC each is perpendicular to AC such that PA-x, RC y, QB=z, AB=a and BC=b. Prove that 1/x + 1/y = 1/z artwork
Q3. In the given figure PA, QB and RC each is perpendicular to AC such that PA-x, RC y, QB=z, AB=a and BC=b. Prove that 1/x + 1/y = 1/z

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 4 min
episode Q2. In triangle ABC, AD is perpendicular to BC and AD x AD = BD.CD .Prove that angle BAC = 90. artwork
Q2. In triangle ABC, AD is perpendicular to BC and AD x AD = BD.CD .Prove that angle BAC = 90.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 4 min
episode Q1. Diagonals AC and BD of a trapezium ABCD with AB II DC intersect each other at point 0. Using similarity criteria for two triangles, show that OA/OC = OB/OD. artwork
Q1. Diagonals AC and BD of a trapezium ABCD with AB II DC intersect each other at point 0. Using similarity criteria for two triangles, show that OA/OC = OB/OD.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

16 oct 2020 - 2 min
Soy muy de podcasts. Mientras hago la cama, mientras recojo la casa, mientras trabajo… Y en Podimo encuentro podcast que me encantan. De emprendimiento, de salid, de humor… De lo que quiera! Estoy encantada 👍
Soy muy de podcasts. Mientras hago la cama, mientras recojo la casa, mientras trabajo… Y en Podimo encuentro podcast que me encantan. De emprendimiento, de salid, de humor… De lo que quiera! Estoy encantada 👍
MI TOC es feliz, que maravilla. Ordenador, limpio, sugerencias de categorías nuevas a explorar!!!
Me suscribi con los 14 días de prueba para escuchar el Podcast de Misterios Cotidianos, pero al final me quedo mas tiempo porque hacia tiempo que no me reía tanto. Tiene Podcast muy buenos y la aplicación funciona bien.
App ligera, eficiente, encuentras rápido tus podcast favoritos. Diseño sencillo y bonito. me gustó.
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La App va francamente bien y el precio me parece muy justo para pagar a gente que nos da horas y horas de contenido. Espero poder seguir usándola asiduamente.

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