Q1. A quadrilateral ABCD is drawn to circumscribe a circle, as shown in the figure. Prove that AB + CD = AD + BC.

Q4. Prove that the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the[l center of the circle

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Q3. Prove that the parallelogram circumscribing a circle is a rhombus.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

Q2. In the given figure, ABCD is a quadrilateral such that angle D = 90. A circle with centre 0 and radius r, touches the sides AB, BC, CD and DA at P, Q, R and S respectively. If BC = 40cm, CD = 25cm and BP = 28cm, find r.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

Q1. A quadrilateral ABCD is drawn to circumscribe a circle, as shown in the figure. Prove that AB + CD = AD + BC.

This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||